Crazy For Bicycles

4 Responses to “The owner of a bicycle shop reported his inventory of bicycles and tricycles in an unusual way. He said he co?”

1. δoτ Says:
   April 2nd, 2010 at 6:01 pm

   If we use b as the number of bikes and t and the number by trikes then using his count we can create the system of equations
   2b + 3t = 126 <– each bike has 2 wheels, and each trike 3
   2b + 2t = 108 <– both have 2 pedals each.

   Solve that system and you’ll get the number of bikes and trikes, the elimination method works fantastically here.

2. IggyRocko Says:
   April 2nd, 2010 at 6:01 pm

   Let b = number of bicycles and t = number of tricycles.
   2b + 3t = 126
   2b + 2t = 108
   solve the system of equations:
   2b = 126 – 3t
   2b = 108 – 2t
   126 – 3t = 108 – 2t
   18 = t
   2b + 2(18) = 108
   2b = 108 – 36 = 72
   b = 36

3. Ed I Says:
   April 2nd, 2010 at 6:01 pm

   Each bike and trike has 2 pedals.

   Let b = no of bikes
   and t = no of trikes

   2b + 2t = 108

   A bike has two wheels and a trike has 3.

   2b + 3t = 126

   Subtracting, t = 18
   2b + 2(18) = 108
   2b + 36 = 108
   2b = 72
   b = 36

   There are 36 bikes and 18 trikes.

4. Rik Says:
   April 2nd, 2010 at 6:01 pm

   Let 2 be the # of wheels on each bike and 108 be the # of pairs of pedals on the back shelf of the store.
   So, 63 bikes and 108 pairs of pedals in the back.